Using the letters and numbers A D L 8 4 and 8 what is the pr

Using the letters and numbers A, D, L, 8, 4, and 8, what is the probability that a 6-space license plate would spell L84AD8?

Solution

Solution :

Number of all posible of arrangement without repetion of using letters and numbers A , D , L ,8 , 4, and 8 = 6!/2!

= 6!/2A!

Since L84AD8 is unique there fore it can be done in one way =

therefore requred probibity = 1 /(6!/2!) = 1/360

Answer: 1/360

 Using the letters and numbers A, D, L, 8, 4, and 8, what is the probability that a 6-space license plate would spell L84AD8?SolutionSolution : Number of all po

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