Evaluate 2kN2Solutionwe know we can convert this to an integ

Solution

we know, we can convert this to an integral by substituting,

1/N = dx

k/N = x

and, in the last term , N/N -> 1

SO, we can say that this summation can be represented as :

integration from 0 to 1 of (2x) dx

which gives as : x² from 0 to 1

which on evaluating comes out as = 1

:)