The uniform dresser has a weight of 85 lb and rests on a til
The uniform dresser has a weight of 85 lb and rests on a tile floor for which ?s = 0.21. If the man pushes on it in the direction ? = 30?, determine the smallest magnitude of force F needed to move the dresser. Also, if the man has a weight of 156 lb , determine the smallest coefficient of static friction between his shoes and the floor so that he does not slip
Determine the smallest magnitude of force F needed to move the dresser.
Solution
Apply the Newton\'s second law, the horizontal force is
Fcos30-0.21*N =0
Along the vertical direction
N-85-Fsin30=0
Solve the two equations, we get
N=96.73 lb
F=23.46 lb. ......answer
...........
The normal force is
Nm = 156 -Fsin30 = 144.27 lb
The force is
Fm = Fcos30=20.3 lb
Hence the coefficient of friction
u = Fm/Nm =0.14
