Need a C Program that prints this Player1 it is your turn Pl

Player-1 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: why I\'m sorry, I do not understand. Please enter your choice (p)aper, (r)ock, or (s)cissors: 42 I\'m sorry, I do not understand. Please enter your choice (p)aper, (r)ock, or (s)cissors: Paper! Player-2 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: r Playerl wins! Paper covers rock! Do you wish to continue? (y/n): y Player-1 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: s Player-2 it is your turn! Please enter your choice (p)aper, (r)ock, or (s)clssors: Rock on! Player2 wins! Rock breaks scissors! Do you wish to continue? (y/n): n Program ended with exit code: 0

Solution

#include <stdio.h>
#include <conio.h>

main ()
{
char p1, p2, q;
clrscr ();
printf (\"\ Player-1 it is your turn: \");
p1=getche ();
printf (\"\ Player-2 it is your turn: \");
p2=getche ();

if (((p1==\'p\')||(p1==\'P\')) && ((p2==\'R\') || (p2==\'r\')))

{
  printf (\"\ Player 1 Wins !\");
  printf (\" Paper Covers Rock\");
}

else if (((p2==\'p\') || (p2==\'P\')) && ((p1==\'r\') || (p1==\'R\')))

{
printf (\"\ Player 2 Wins !\");
printf (\"Paper Covers Rock\");
}

else if (((p1==\'r\') || (p1==\'R\')) && ((p2==\'s\') || (p2==\'S\')))

{
printf (\"\ Player 1 Wins !\");
printf (\"Rock Breaks Scissors\");
}

else if (((p2==\'r\') || (p2==\'R\')) && ((p1==\'s\') || (p1==\'S\')))

{
printf (\"\ Player 2 Wins !\");
printf (\"Rock Breaks Scissors\");
}

else if (((p1==\'s\') || (p1==\'S\')) && ((p2==\'p\') || (p2==\'P\')))

{
printf (\"\ Player 1 Wins !\");
printf (\"Scissors Cut Paper\");
}

else if (((p2==\'s\') || (p2==\'S\')) && ((p1==\'p\') || (p1==\'P\')))
{
printf (\"Player 2 Wins !\");
printf (\"Scissors Cut Paper\");
}

else if (p1==p2)
{
printf (\"\ Nobody Wins !\");
printf (\"\ Both Of You Entered The Same Letters\");
}

else {

printf (\"\ I am Sorry, I do not uderstand.\");
printf (\"\ Enter Only Letters : P,S or R\");
}
printf(\"\ Do you wish to continue? (y/n) \" );

q=getche ();

if (quit=n){

return 0;

}

getch ();

}