Let X be a normal random variable with a mean of 033 and a s

Let X be a normal random variable with a mean of 0.33 and a standard deviation of 2.69.

a)Calculate the corresponding standardized value (z) for the point x = 4.1. Give your answer to 2 decimal places.

z =

b)The area under the standard normal probability density function from negative infinity to z is interpreted as the probability that the random variable is:

Solution

(a) Z=(X-mean)/s

=(4.1-0.33)/2.69

=1.40

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(b) less than or equal to z