An IQ test was administered to a random sample of 101 sixth

An IQ test was administered to a random sample of 101 sixth graders. The sample mean was 104.2 with a standard deviation of 12. Calculate the maximum error of estimate of the population mean with a 99% confidence interval.

Need step by step please.

Solution

Confidence Interval
CI = x ± t a/2 * (sd/ Sqrt(n))
Where,
x = Mean
sd = Standard Deviation
a = 1 - (Confidence Level/100)
ta/2 = t-table value
CI = Confidence Interval
Mean(x)=104.2
Standard deviation( sd )=12
Sample Size(n)=101
Confidence Interval = [ 104.2 ± t a/2 ( 12/ Sqrt ( 101) ) ]
= [ 104.2 - 2.626 * (1.194) , 104.2 + 2.626 * (1.194) ]
= [ 101.064,107.336 ]