19 The normal order of the genes on two chromosomes are ABCD
19. The normal order of the genes on two chromosomes are ABCD.EFGH and STUV.WXYZ where the periods represent the centromeres. Match the gene orders given with the chromosomal aberration that they represent.
ABFE.DCGH and STUV.WXYZ
ZYCD.EFGH and STUV.WXBA
ABCD.EFGH and STUV.WXYXYZ
Answer 3 Choose...Reciprocal Translocation, Paracentric Inversion, Terminal Deletion, Interstitial Deletion, Pericentric Inversion, Tandem Duplication, Robertsonian Translocation, Reverse Tandem Duplication
| ABFE.DCGH and STUV.WXYZ | Answer 1 Choose...Reciprocal Translocation, Paracentric Inversion, Terminal Deletion, Interstitial Deletion, Pericentric Inversion, Tandem Duplication, Robertsonian Translocation, Reverse Tandem Duplication |
| ZYCD.EFGH and STUV.WXBA | Answer 2 Choose...Reciprocal Translocation, Paracentric Inversion, Terminal Deletion, Interstitial Deletion, Pericentric Inversion, Tandem Duplication, Robertsonian Translocation, Reverse Tandem Duplication |
| ABCD.EFGH and STUV.WXYXYZ | Answer 3 Choose...Reciprocal Translocation, Paracentric Inversion, Terminal Deletion, Interstitial Deletion, Pericentric Inversion, Tandem Duplication, Robertsonian Translocation, Reverse Tandem Duplication |
Solution
1: ABFE.DCGH and STUV.WXYZ
Since the \"CD.EF\" region of first chromosome is broken and then ligated in reverse order, it is pericentric inversion.
2: ZYCD.EFGH and STUV.WXBA
Since there is one break in each chromosome followed by exchange of broken part between the chromosomes, it is reciprocal translocation.
3: ABCD.EFGH and STUV.WXYXYZ
Since there is duplication of chromosome region containing \"XY\" genes and the duplicated reiog is present adjacent to the original one, it is tendem duplication.
