The Bay of Fundy in North America has some of the largest va
Solution
HEre the required model will be represented by the sine function o f form
y=Asin Bx
Here amplitude A =17-3= 14
and its half period pi/B = 18-11=7
so B= 3.14/7 = 0.4486
so required function is y=14sin (0.4486x)
Now when for 1:00 A.M. x= 2, so
y= 14 sin (0.4486 x 2) = 14 sin(0.8971) =14 x 0.7815 = 10.94
So at 1:00 pm, it is 10.94 ft deep.
Answer of part a)
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Now for second part, we differentiate above function with respect to x as :
dy/dx = 14cos (0.4486x)(d/dx)(0.4486x) = 14(0.4486) cos (0.4486x) =6.2804 cos (0.4486x)
Now as 8 p.m. , x= 9
so at this point dy/dx = 6.2804 cos (0.4486(9)) = 6.2804cos(4.0374) = 6.2804 x (-0.6249) = -3.92
that means (-) signn shows that its direction is downwards towards lowtide and its seed is 3.92 m per hour.
Answer

