how to find current through each phase impedance Fig EAB 208
how to find current through each phase impedance?
Fig EAB 208 V20 ECA = 208 VL03 vza, S 22 22 22 BC = 208 V L.Solution
here the load is delta connected load.
so, in delta connected load
line voltage =phase voltage.
EAB=Eab=208<0 volts.
EBC=Ebc=208<+120 volts.
ECA=Eca=208<-120 volts.
current through phase ab=Iab=(208<0)/22=9.45<0 amps.
current through phase bc=Ibc=(208<120)/22=9.45<120 amps.
currrent through phase ac=Iac=(208<-120)/22=9.45<-120 amps.

