Please SHOW ALL WORK TO RECIEVE FULL CREDIT PLEASE ALL 4 PAR
Please SHOW ALL WORK TO RECIEVE FULL CREDIT!!!
PLEASE ALL 4 PARTS..
Solution
(1) X~Binomial(n=5, p=0.04)
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(2)the sum of the probabilities =1
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(3)
There is 5C0 =1 way that you can select 0 products out of group of 5
There are 5C1=5 ways that you can select 1 products out of group of 5
There are 5C2 =(5*4/2)=10 ways that you can select 2 products out of group of 5
There are 5C3 = 10 ways that you can select 3 products out of group of 5
There are 5C4=5 ways that you can select 4 products out of group of 5
There are 5C5=1 way that you can select 5 products out of group of 5
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(4)The sum of all of those products =0.2 which is the mean
| cumulative | ||
| X | P(X) | probability |
| 0 | 0.81537 | 0.81537 |
| 1 | 0.16987 | 0.98524 |
| 2 | 0.01416 | 0.99940 |
| 3 | 0.00059 | 0.99999 |
| 4 | 0.00001 | 1.00000 |
| 5 | 0.00000 | 1.00000 |
