Find the maximum and minimum of fx 5 x 2 and 4 lessthanor

Find the maximum and minimum of f(x) = 5 + |x - 2| and -4 lessthanorequalto x lessthanorequalto 3. Find the local maximum and minimum of f(x) = x^3 + 3x^2 - 9x + 7.

Solution

5. To find the maximum and minimum of y= 5+ abs(x-2)   , we have to use graph

From this graph we can say that the given function is maximum at x=-4 which is

y= 5 + abs(-4-2) = 5+6=11

And minimum is at x=2 which is

y=5 + abs(2-2) = 5