The NCHS reported mean total cholesterol level for all adults is .203. Suppose a new drug is proposed to lower cholesterol. A study is designed to evaluate the efficiency of the drug in lowering cholesterol. Fifteen patients are enrolled in the study and asked to take the new drug for 6 weeks. At the end of 6 weeks, each patient\'s total cholesterol level is measured and the sample statistics are as follows: n= 15, x= 195.9 and s=28.7. Is there statistical evidence of the reduction in mean total cholesterol in patients after using the new drug for 6 weeks under level of significance .05?
The NCHS reported mean total cholesterol level for all adults is .203. Suppose a new drug is proposed to lower cholesterol. A study is designed to evaluate the efficiency of the drug in lowering cholesterol. Fifteen patients are enrolled in the study and asked to take the new drug for 6 weeks. At the end of 6 weeks, each patient\'s total cholesterol level is measured and the sample statistics are as follows: n= 15, x= 195.9 and s=28.7. Is there statistical evidence of the reduction in mean total cholesterol in patients after using the new drug for 6 weeks under level of significance .05?
The NCHS reported mean total cholesterol level for all adults is .203. Suppose a new drug is proposed to lower cholesterol. A study is designed to evaluate the efficiency of the drug in lowering cholesterol. Fifteen patients are enrolled in the study and asked to take the new drug for 6 weeks. At the end of 6 weeks, each patient\'s total cholesterol level is measured and the sample statistics are as follows: n= 15, x= 195.9 and s=28.7. Is there statistical evidence of the reduction in mean total cholesterol in patients after using the new drug for 6 weeks under level of significance .05?
Formulating the null and alternative hypotheses,
Ho: u >= 203
Ha: u < 203
As we can see, this is a left tailed test.
Thus, getting the critical t,
df = n - 1 = 14
tcrit = - 1.761310136
Getting the test statistic, as
X = sample mean = 195.9
uo = hypothesized mean = 203
n = sample size = 15
s = standard deviation = 28.7
Thus, t = (X - uo) * sqrt(n) / s = -0.9581248
Also, the p value is
p = 0.177127333
As |t| < 1.761, or P > 0.05, we FAIL TO REJECT THE NULL HYPOTHESIS.
Thus, there is no significant evidence of the reduction in mean total cholesterol in patients after using the new drug for 6 weeks under level of significance 0.05. [CONCLUSION]
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