Part A How much energy is stored in a 290cmdiameter 140cmlon

Part A How much energy is stored in a 2.90-cm-diameter, 14.0-cm-long solenoid that has 200 turns of wire and carries a current of 0.760 A ?

Express your answer with the appropriate units.

Please show all steps and work clearly, thank you. :)

The solenoid is an inductor therefore:

Energy stored in inductor field, E = ½*L*i² (L=solenoid self inductance in H, i=current in A)

L for solenoid .. L = .A.n² / l .. (A= coil area, n=No.of turns, l=length)

combining equations.

E = ½..A.n² i² / l ..

E = ½(4^-7)([1.45*10^-2]²)(200²)(0.76²) / (0.14) .. (distances converted to metres)

E= 0.0000684 = 6.84*10^-5 J