We selected a random sample of size 120 from a pool of unive

We selected a random sample of size 120 from a pool of university students and asked whether they use Facebook on a regular basis. Fifty replied yes. What would be your estimation of the standard error of the sample proportion of regular Facebook users based upon the given information?

Solution

Solution;

Proportion of successes (p)=50/120 =0.417

Number of observations (n)=120

standard error of the sample proportion=SE_p

Formula used:

SE_p = sqrt [ p ( 1 - p) / n]

where, p is Proportion of successes in the sample,n is Number of observations in the sample.

=sqrt(0.417(1-0.417)/120)

=0.0450