A 4 long key has a 5 wide by 75 high cross section If the to

A 4\" long key has a .5\" wide by .75\" high cross section. If the torque on the 2.4\" diameter shaft is 1200 in.lb, what is the shear stress on the key?

Solution

Given: Torque= 1200, wide=0.5, length=4

shear stress = (2*torque)/(diamter*wide*length)

Shear stress= (2*1200)/(2.4*0.5*4)

Shear stress on key = 500 lb/in^2