1 What are the solutions to secant sec 322 in the interval

1 - What are the solutions to secant sec( 3/2)=2 in the interval 0<2?

2 - Solve the equation on the interval 0<2. 6cos+3=0

3 - Solve the equation on the interval 0<2. (3 times square root 2)cos+1=2

4- Solve the equation. Give a general formula for all the solutions. List six solutions. sin=1/2

Thank you!!

1)sec( 3/2)=2

03/2<3

3/2=pi-(pi/3),pi+(pi/3),3pi-(pi/3)

3/2=(2pi/3),(4pi/3),(8pi/3)

=(2/3)(2pi/3),(2/3)(4pi/3),(2/3)(8pi/3)

=(4pi/9),(8pi/9),(16pi/9)

2) 6cos+3=0

cos=-3/6

cos=-1/2

=pi-(pi/3),pi+(pi/3)

=2pi/3,4pi/3