5 Let EX for a random variable X Compute E2x 5 Solution5 As

5. Let -E(X) for a random variable X. Compute E(2x + 5)

Solution

5.

As

E(2x + 5) = 2E(x) + 5

and

E(x) = u

Then

E(2x + 5) = 2u + 5 [ANSWER]

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 5. Let -E(X) for a random variable X. Compute E(2x + 5) Solution5. As E(2x + 5) = 2E(x) + 5 and E(x) = u Then E(2x + 5) = 2u + 5 [ANSWER] *********************

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