Find the domain of the variable in the interval form in the

Find the domain of the variable (in the interval form) in the expression squareroot x^2 - 7x + 12/(1 - 2x)^2.

Solution

sqrt((x2-7x+12)/(1-2x)2)

(1/(1-2x))sqrt((x-3)(x-4))

Here we have (x-3)(x-4) inside the square root

And it must be greater then 0

(x-3)(x-4)>=0

x>=4 or x <=3

and we have a rational term too

And the denominator cant be zero

1-2x=0

x=1/2

hence the domain is (-inf, 1/2)U(1/2,3]U[4,inf)

 Find the domain of the variable (in the interval form) in the expression squareroot x^2 - 7x + 12/(1 - 2x)^2.Solutionsqrt((x2-7x+12)/(1-2x)2) (1/(1-2x))sqrt((x

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