The schematic symbol for an Nchannel JFET is shown in the fi

The schematic symbol for an N-channel JFET is shown in the figure. For tins device to be biased properly, the gate must be A. at the same potential as the source B. positive with respect to the source. C. negative with respect to the source. D. at the same potential as the drain. Use this illustration to answer the question. Look at the circuit diagram shown in the figure. If you momentarily press and release switch S_4, and then momentarily press switch S_1, what voltage would you measure across capacitor C_1? A. 0 V B. 6.3 V C. 22 V D. 10 V Use this illustration to answer the question. In the circuit shown in the figure, if the voltage from the variable DC power supply was 3 V, what would be the measured voltage between points B and C? A. 0 V B. 3 V C. 5.6 V D. 2.6 V A forward-biased PN junction will have a positive voltage applied to the P side and a voltage applied to the N side. A. higher B. lower C. negative D. positive Use this illustration to answer the question. A transistor amplifier circuit and its characteristic curve are shown in the figure. The transistor amplifier circuit is to be biased for linear operation so that the output signal is an amplified replica of the input signal. To achieve this goal, at winch of the following points on the characteristic curve should this amplifier be biased? A. At point A B. At point C C. Midway between points a and C D. Midway between points A and B Imagine that you\'re working with the bars shown in Figure A-1. If one end of bar A repels one end of bar B and attracts the other end of bar B. your conclusion should be that A. only bar A is magnetized B. only bar B is magnetized. C. either bar A or bar B is magnetized D. both bars are magnetized. Use this illustration to answer the question. In the circuit shown in the figure, if the voltage from the variable DC power supply was 3 V, what would be the measured voltage between points A and B? A. 5.6 V B. 2.6 V C. 0 V D.3 V

Solution

8 Ans) C-negative with respect to source

Because negative gate voltage causes conducting channel to become narrower and adjusted such that operating point is in the active region of Drain charchteristics.And also Value of drain-source voltage, VDS for breakdown with the increase in negative bias voltage is reduced simply due to the fact that gate-source voltage, VGS keeps adding to the I reverse bias at the junction produced by current flow

Hence for working of JFET in the pinch-off or active region it is necessary that the following conditions be fulfilled.

VP < VDS < VDS (max)

VGS (OFF)< VGS < 0

0 < ID < IDSS

From the above we can see that VGS<0 i.e negative

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