For the triangle ABC we are given that A 48 B 62 and c 35

For the triangle ABC, we are given that A = 48°, B = 62°, and c = 35.0.

Find the length of side a, rounded to the nearest tenth. Show work.

Solution

A = 48°,

B = 62°,

C = 180 - 48 - 62 = 70

and c = 35.0

If A, B, and C are the measures of the angles of a triangle, and a, b, and c are the lengths of the sides opposite these angles, then

sinA/a = sinB/b = sinC/c

sin48/a = sin70/35

a = 35*sin48/sin70 = 27.7