Train A leaves moving at 100mph and passes a station at 920p

Train A leaves moving at 100mph and passes a station at 9:20pm
Train B leaves moving at 125mph and passes the same station at 9:32
what time will train B catch up to train A

Solution

100T=125(T-.2)
100T=125T-25
100T-125T=-25
-25T=-25
T=-25/-25
T=1 HOUR AFTER TRAIN A LEAVES THEY WILL MEET.
9:20+1:00=10:20 TIME OF THE MEETING.
PROOF:
100*1=125(1-.2)
100=125*.8
100=100