A study determined that 4 of children under 18 years old Kve

A study determined that 4% of children under 18 years old Kved with their father only. Find the probability that none of the children selected at random from 11 children under 18 years old Kved with their father only. The probability that none of the children Kved with their father only is.

Solution

p = 4% = 0.04

q = 1- 0.04 = 0.96

Binomial probability distribution: nCr(p)^r(q^(n-r) )

n = 25 ; r =0

Probability that none of children live with their father only

= 25C0(0.04)^0(0.96)^25

= 0.96^25

= 0.360