As shown below a metal wire of mass m 241 mg can slide with

As shown below, a metal wire of mass m = 24.1 mg can slide with negligible friction 011 two horizontal parallel rails separated by a distance d = 2.56 cm. The track lies in a vertical uniform magnetic field of magnitude B = 56.3 mT. At time t = 0, the wire is at rest and device G is connected to the rails, producing a constant current I = 9.13mA in the wire and rails (even as the wire moves).

Solution

F = i L B = 9.13 * 10-3 * 0.0256 * 56.3 * 10-3

= 1.32 * 10-5 N

F = m a

a = F / m

= 1.32 * 10-5 / 0.0241 kg

= 5.47 * 10-4 m/s2

 As shown below, a metal wire of mass m = 24.1 mg can slide with negligible friction 011 two horizontal parallel rails separated by a distance d = 2.56 cm. The

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site