Directions For each problem show the necessary work and indi

Directions: For each problem, show the necessary work and indicate clearly your answer. (HW Supp 10 has 2 pages.) In the box shown, 32% of the tickets are l\'s and 68% of the tickets are 0\'s. the average of the tickets in the box = the standard deviation of the tickets in the box = On a certain biased coin, heads is twice as likely as tails. That is, P(H) = 2/3. The number of times the coin lands on heads in 900 tosses is like the SUM of 900 draws, with replacement, from the box: the expected number of heads in 900 tosses = the standard error for the number of heads in 900 tosses = the expected percentage of heads in 900 tosses - the standard error for the percentage of heads in 900 tosses =

Solution

1) Average of tickets in the box = 32(1) +68(0) = 32%=0.32

2) Variance = (32-32)1^2+(68-32)0^2 = 0

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P(Head) =2/3

Average of head in 900 tosses = 900(2/3) = 600

Variance = npq = 600(1/3) = 200

Std dev = rt of variance = 14.142

std error = 14.142/rt 900 = 0.4714

Expected percent in 900 tosses = 66.67%

Std error = 0.4714