Need help Directions are solve the equation x2312x3120Soluti

Need help. Directions are solve the equation (x^2-3)^1/2-(x+3)^1/2=0

(x^2-3)^1/2-(x+3)^1/2=0

(x^2-3)^1/2 = -(x+3)^1/2

Squaring both sides: (x^2 -3) = (x+3)

Now using a^2 -b^2 = (a+b)(a-b)

(x+ 3)( x-3) - (x+3) =0

(x+3) { x-3 -1 } =0

(x +3)( x -4) =0

x =-3; x =4 (solution)