A 100 ohm a 02 H are capacitor are connected in mariam to a

A 100 ohm a 0.2 H. are capacitor are connected in mariam to a 110V 60 Hz.

Impedence

Z = sqrt(R^2 + (XL - XC)^2)

R = 100 ohm

XL = wL = 2*pi*f*L

XL = 2*3.14*60*0.2 = 75.36 ohm

XC = 1/wC = 1/2*pi*f*C = 1/(2*3.14*60*3*10^-6) = 884.64 ohm

Z = sqrt(100^2 + (75.36 - 884.64)^2)

Z = 815.43 ohm

Correct option is B.