Find gx the inverse of fx log402 Solutiony log2 4x 2 y 2



Find g(x), the inverse of f(x) = log(40-2.

Solution

y = log2 (4x) - 2

y -2 = log (4x) / log 2

(y-2) log 2 = log (4x)

0.3 (y - 2) = log 4x

0.3 y - 0.6 = log 4x

antilog ( 0.3 y - 0.6 ) = 4x

x = [antilog (0.3 y - 0.6 )]/4

g(x) = [antilog (0.3 x - 0.6 )]/4

 Find g(x), the inverse of f(x) = log(40-2. Solutiony = log2 (4x) - 2 y -2 = log (4x) / log 2 (y-2) log 2 = log (4x) 0.3 (y - 2) = log 4x 0.3 y - 0.6 = log 4x a

Get Help Now

Submit a Take Down Notice

Tutor
Tutor: Dr Jack
Most rated tutor on our site