A proton is moving in the x direction with a speed of 479 km

A proton is moving in the -x direction with a speed of 479 km/s through a region containing a uniform 2.12 T magnetic field that points in the -y direction. What is the magnitude of the magnetic force on the proton?

Solution

F = qVB*sin A

sin A = sin 90 = 1

F = 1.6*10^-19*2.12*479*10^3 = 1.62*10^-13 N