PHYS 2426 501 Spring 2016 Chapter 28 Question 2 Question 2 A
Solution
Each loop of wire is d long = *3.00cm = 9.42cm = 0.0942m
So the wire is 15.0m long so it can make 15/0.0942 = 159 loops
So the solenoid is 2.0mm*159 = 318mm or 31.8cm long
So now there are 159turns/0.318m = 500 turn per meter
Now the B field at the center is µo*n*i = 4x10^-7*500*15 = 9.45x10^-3T
