For the following sequences xn 4 5 1 2 3 0 2 3 lessthanoreq
Solution
w[n+2] is the 2 unit delayed version of w(n) = { 3 2 2 -1 0 -2 5} 0<= n <= 6
x[n/2] gives you the expansion in time domain.in expansion x[n/a] means inserting two zeroes between the values
x[n] ={ -4 5 1 -2 -3 0 2 } and x[n/2] = { -4 0 0 5 0 0 1 0 0 -2 0 0 3 0 0 0 0 0 2 } x[2n] means removing the odd value as the n is multiplied with 2 and if n is multiplied by odd number then even values are removed. x[2n] = {5 -2 0}
- 1<n<1 and w[n/2] = { 3 0 0 2 0 0 2 0 0 -1 0 0 0 0 0 -2 0 0 5} where 4 < n < 16
adding all three sequences by according to the starting time of each sequence,
x[2n] = 5 -2 0 -1<n<1
y[n] = 6 -3 -1 0 8 7 -2 -1<n<5
w[n/2] = 3 0 0 2 0 0 2 0 0 -1 0 0 0 0 0 -2 0 0 5 4<n<12
adding all the three sequences u[n] = { 11 -5 -1 0 8 10 -2 0 2 0 0 2 0 0 -1 0 0 0 0 0 -2 0 0 5 }
![For the following sequences: x[n] = {-4 5 1 -2 -3 0 2), -3 lessthanorequalto n lessthanorequalto 3 y[n] = {6 -3 -1 0 8 7 -2}, -1 lessthanorequalto n lessthanor For the following sequences: x[n] = {-4 5 1 -2 -3 0 2), -3 lessthanorequalto n lessthanorequalto 3 y[n] = {6 -3 -1 0 8 7 -2}, -1 lessthanorequalto n lessthanor](/WebImages/8/for-the-following-sequences-xn-4-5-1-2-3-0-2-3-lessthanoreq-995734-1761512469-0.webp)