Ch333If possible can you please answer as many as possible Y

Ch3...33>>>If possible can you please answer as many as possible. Your help is greatly appreciated. Have a great Day!

Solution

33.   (Problem 32c) The following two genotypes are crossed: AaBbCcddEe × AabbCcDdEe. What will be the proportion of the genotype aabbccddee among the progeny of this cross?

   C. 1/256

Explanation:

The probability of any offspring being aabbccddee is

aa = 1/ 4, bb = 1 /2, cc = 1/4, dd=1/2, ee=1/4

Therefore, aabbccddee = 1/4 × 1/2 × ¼ x ½ x 1/4 = 1/256

34.   (Problem 32d) The following two genotypes are crossed: AaBbCcddEe × AabbCcDdEe. What will be the proportion of the genotype AABBCCDDEE among the progeny of this cross?

   E. Will not occur

The probability of any offspring being AABBCCDDEE is

AA = 1/ 4, BB = 0, CC = 1/4, DD=0, EE=1/4

Therefore, AABBCCDDEE = 0