The solutions in the two arms of this Utube are separated by

The solutions in the two arms of this U-tube are separated by a membrane that is permeable to water and glucose but not to sucrose. Side A is half-filled with a solution of 2 M sucrose and 1 M glucose. Side B is half-filled with 1 M sucrose and 2 M glucose. Initially, the liquid levels on both sides are equal. Initially, in terms of tonicity, the solution in side A with respect to that in side B is ISQTQNIC After the system reaches equilibrium, what changes are observed? Which side would be higher? What if the U-tube separated by a membrane that is permeable to EVERYTHING. What changes would be observed? What if the solute concentration was different... Side A is now half-filled with a solution of 3 M sucrose and 1 M glucose. Side B is half-filled with 2 M sucrose and 4 M glucose. Initially, the liquid levels on both sides are equal. In terms of tonicity, the solution in side A with respect to that in side B is b After the system reaches equilibrium, what changes are observed? Which side would be higher?

Solution

b)

a) Initially, the solution in side A is isotonic with respect to that in side B after equilibrium glucose will move from side B to Side A. There will be 2.0 M sucrose and 1.5 M glucose on side A . There will be 1.0 M surcose and 1.5 M glucose on side B.   side B has more water, therefore, water will move from side B to side A and side A will rise.

b) if membrane is permeable to everything side B will rise

If solute concentration different

a) isotonic

b) because if you add both side together, they are both of isotonic

Side A	Side B
2 M sucrose	1M sucrose
1M glucose	2M glucose