A heat engine receives heat from a source at 1727oC at a rat
A heat engine receives heat from a source at 1727oC at a rate of 500 kW and rejects the waste heat to the atmosphere at 27oC. The net output from the engine is 300 kW. Determine:
a. The reversible power output
b. The rate of exergy flux into the engine
c. The rate of irreversibility (exergy destruction) in the universe
d. The second-law (exergy) efficiency of the engine
Solution
T1= 1727+273= 2000 K
T2 = 27+273= 300 K
CARNOT EFFICIENCY= 1-(300/2000)= 0.85
CARNOT EFFICIENCY= W/Q1=0.85
W/500= 0.85
SOLVING a) REVERSIBLE POWER OUTPUT= W= 425 KW
B) RATE OF EXERGY FLUX= 500 KW
C) RATE OF EXERGY DESTRUCTION= 425-300= 125 KW
D) CYCLE EFFICIENCY= 300/500= 0.60
SECOND LAW EFFICIENCY= 0.60/0.85= 0.70588
