A solenoid with 30000 turns is 1000 cm long If its selfinduc

A solenoid with 3000.0 turns is 100.0 cm long. If its self-inductance is 37.0 mH, what is its radius? (lhe value of Ho is 4 × 10-7 N/A2.) A) 53 m B) 0.00203 nm C) 333 m D) 0.03227 m

Solution

L = u*N^2*pi*r^2*l

given,

L = 37.0 mH = 37*10^-3 H

L = 100 cm = 100*10^-2 m

N = 3000 turns

r = sqrt[37*10^-3/(4*3.14*10^-7*3000^2*3.14*100*10^-2)]

r = 0.03227 m