Constructing the real numbers Intro real analysis Exhibit t
Solution
a) A and B are two subsets of Q.
Given that a<=b for all a in A and b in B.
This implies that set A is bounded above and set B is bounded below
There is a supremum l for A and m infremum for B.
If supremum of A = infremum of B, and they do not belong to A and B
then highest element in A<inf and sup < lowest element in B.
Thus proved
They are equal if both belong to the sets
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b) Same proof holds good for real numbers also.
c) If AUB =R
then it implies that A and B are mutually exhaustive.
There is no element in r which is not in A and B.
Hence supremum of A being a real number must be either in A or in B.
If it is in A, then that is infremum for B, and this r is unique.
Similarly if it is in B, then that is supremum of A.

