find the area of the region bounded by ycoshx the x axis and
find the area of the region bounded by y=cosh(x), the x axis and the vertical lines x=0 and x=ln 3(remember cosh(x)=(e^x+e^-x)/2.
Solution
the area of the region bounded by y=cosh(x), the x axis and the vertical lines x=0 and x=ln 3(remember cosh(x)=(e^x+e^-x)/2. Area = integral[cosh x dx ] from x =0 to ln 3 Area = integral [(e^x+e^-x)/2]dx from x =0 to ln3 = 0.5[e^x- e^-x] from x = 0 to ln 3 =0.5*{[3-1/3] -[1-1]} = 0.5*8/3 =4/3 units