An73 Bn44 Cn72 Dn103 Find the minimum sample size when we wa
A)n=73
B)n=44
C)n=72
D)n=103
Find the minimum sample size when we want to construct a 90% confidence interval on the population proportion for the support of candidate A in the following mayoral election. Candidate A is facing two opposing candidates. In a preselected poll of 100 residents, 22 supported her. The desired margin of error is 0.08.Solution
Note that      
       
 n = z(alpha/2)^2 p (1 - p) / E^2      
       
 where      
       
 alpha/2 =    0.05  
        
       
 Using a table/technology,      
       
 z(alpha/2) =    1.644853627  
       
 Also,      
       
 E =    0.08  
 p =    0.22  
       
 Thus,      
       
 n =    72.54238386  
       
 Rounding up,      
       
 n =    73   [ANSWER, A]

