An73 Bn44 Cn72 Dn103 Find the minimum sample size when we wa
A)n=73
B)n=44
C)n=72
D)n=103
Find the minimum sample size when we want to construct a 90% confidence interval on the population proportion for the support of candidate A in the following mayoral election. Candidate A is facing two opposing candidates. In a preselected poll of 100 residents, 22 supported her. The desired margin of error is 0.08.Solution
Note that
n = z(alpha/2)^2 p (1 - p) / E^2
where
alpha/2 = 0.05
Using a table/technology,
z(alpha/2) = 1.644853627
Also,
E = 0.08
p = 0.22
Thus,
n = 72.54238386
Rounding up,
n = 73 [ANSWER, A]
