Two computer specialists are completing work orders The firs

Two computer specialists are completing work orders. The first specialist receives 60% of all orders. Each order takes her exponential time with parameter =3hrs^-1 . The second specialist receives the remaining 40% of orders. Each order takes him exponential time with parameter =2 hrs ^-1.

A certain order was submitted 30 minutes ago, and is still not ready. What is the probability that the first specialist is working on it?

ANSWER IN THE BOOK IS: 0.4764

Solution

Same question solved here!!!Only values are diffrerent!!! http://www.cramster.com/answers-oct-11/statistics-and-probability/probability-computer-specialists-completing-work-orders-fir_1567293.aspx?rec=0 Hope this helps!!!