Find the zeros for the given polynomial function and give th
Solution
x3- 4x2 + 4x = 0 can be written as x[x2 - 2x - 2x + 4] = 0
=> x[x( x - 2) - 2(x - 2)] = 0
thus x(x - 2) ( x - 2) = 0
this is true for x = 2 and x = 0
therefore the zeros are 0,2
hence the multiplicity of leftmost zero is 1 (it just appears once in our solution) and the multiplicity of 2 is 2 (since our solution gave \'x - 2\' twice).
To find out whether the graph overshoots the x axis, differentiate the given function. This will give:
f \' (x) = 3x2 - 8x + 4
for finding a maxima, the this derivative must be zero.
so 3x2 - 8x + 4 = 0
whose solutions are: x = 2 and x = 2/3
substitute these values in original function to see if f(x) < 0
f(2) = 0
f(2/3) = (2/3)3- 4(2/3)2 + 4(2/3) = 1.185
thus the graph just touches the x axis at x = 2 and never goes below it.
