Stack and Queue C NOTE Must aggregate the array class poste
Stack and Queue - C++
**NOTE: Must aggregate the array class posted below.**
Implement a Stack class using the Array Class you developed earlier. Test your Stack class by determining if the following strings have matching open and closing ( ) and/or [ ] and/or { } and/or < >. The following is one set of data to test your code:
( )
[ ] ( ) { }
[ { ( ) } ]
< > <<< >>>
[ [ ) )
{ ( ) [ ( ) ] }
class Array
{
private:
int begin;
int end;
int *ary;
public:
Array(int n);
Array(int n, int m);
int &operator[](int index);
Array &operator = (Array a);
bool operator == (Array &a);
bool operator != (Array &a);
friend ostream &operator << (ostream &out, Array &a);
friend Array operator + (Array &a, Array&b);
friend Array operator - (Array &a, Array&b);
friend Array operator * (Array &a, Array&b);
friend Array operator / (const Array &a, const Array&b);
};
//Constructor
Array::Array(int n)
{
begin = 0;
end = n - 1;
ary = new int[n];
for (int i = 0; i < n; i++)
ary[i] = i + 1;
}
//Copy constructor
Array::Array(int n, int m)
{
begin = n;
end = m - 1;
ary = new int[m - n];
for (int i = 0; i < m - n; i++)
ary[i] = begin + i;
}
//Overload [] operator
int &Array::operator[](int index)
{
static int element; //Static added to silence reference to stack memory warning
if (index >= begin && index <= end)
{
element = ary[index - begin];
}
else
{
cout << \"Error: Index out of bounds.\" << endl;
element = 0;
}
return element;
}
//Overload the = operator
Array &Array::operator = (Array a)
{
begin = a.begin;
end = a.end;
for(int i = 0; i < end - begin; i++)
{
ary[i] = a.ary[i];
}
return *this;
}
//Overload the == operator
bool Array::operator == (Array &a)
{
for(int i = 0; i < end - begin; i++)
{
if(ary[i] != a.ary[i])
return false;
}
return true;
}
//Overoads the != operator
bool Array::operator != (Array &a)
{
return *this == a;
}
ostream &operator << (ostream &out, Array &b)
{
for(int i = 0; i < b.end - b.begin; i++)
{
out << \"(\" << i << \")\" << b.ary[i] << \" \";
}
return out;
}
//Overload the + operator
Array operator + (Array &a, Array&b)
{
Array arr(a.end - a.begin);
for(int i = 0; i < a.end - a.begin; i++)
{
arr.ary[i] = a.ary[i] + b.ary[i];
}
return arr;
}
//Overloads the subtraction operator
Array operator - (Array &a, Array&b)
{
Array arr(a.end - a.begin);
for(int i = 0; i < a.end - a.begin; i++)
{
arr.ary[i] = a.ary[i] - b.ary[i];
}
return arr;
}
//Overload the multiplication operator
Array operator * (Array &a, Array&b)
{
Array arr(a.end - a.begin);
for(int i = 0; i < a.end - a.begin; i++)
{
arr.ary[i] = a.ary[i] * b.ary[i];
}
return arr;
}
//Overload the division operator
Array operator / (const Array &a, const Array&b)
{
Array arr(a.end - a.begin);
for(int i = 0; i < a.end - a.begin; i++)
{
if (b.ary[i] == 0)
{
arr.ary[i] = 0;
}
else
{
arr.ary[i] = a.ary[i] / b.ary[i];
}
}
return arr;
}
Solution
#include <iostream>
#include <string>
using namespace std;
/* structure of a stack node */
struct sNode
{
char data;
struct sNode *next;
};
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data);
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref);
/* Returns 1 if character1 and character2 are matching left
and right Parenthesis */
bool isMatchingPair(char character1, char character2)
{
if (character1 == \'(\' && character2 == \')\')
return 1;
else if (character1 == \'{\' && character2 == \'}\')
return 1;
else if (character1 == \'[\' && character2 == \']\')
return 1;
else if (character1 == \'<\' && character2 == \'>\')
return 1;
else
return 0;
}
/*Return 1 if expression has balanced Parenthesis */
bool areParenthesisBalanced(char exp[])
{
int i = 0;
/* Declare an empty character stack */
struct sNode *stack = NULL;
/* Traverse the given expression to check matching parenthesis */
while (exp[i])
{
/*If the exp[i] is a starting parenthesis then push it*/
if (exp[i] == \'{\' || exp[i] == \'(\' || exp[i] == \'[\' || exp[i] ==\'<\')
push(&stack, exp[i]);
/* If exp[i] is a ending parenthesis then pop from stack and
check if the popped parenthesis is a matching pair*/
if (exp[i] == \'}\' || exp[i] == \')\' || exp[i] == \']\' || exp[i]==\'>\')
{
/*If we see an ending parenthesis without a pair then return false*/
if (stack == NULL)
return 0;
/* Pop the top element from stack, if it is not a pair
parenthesis of character then there is a mismatch.
This happens for expressions like {(}) */
else if ( !isMatchingPair(pop(&stack), exp[i]) )
return 0;
}
i++;
}
/* If there is something left in expression then there is a starting
parenthesis without a closing parenthesis */
if (stack == NULL)
return 1; /*balanced*/
else
return 0; /*not balanced*/
}
int main()
{
char exp[100] = \"( ) [ ] ( ) { } [ { ( ) } ] < > <<< >>>[ [ (( ) )]]{ ( ) [ ( ) ] }\";
if (areParenthesisBalanced(exp))
printf(\"\ Balanced \");
else
printf(\"\ Not Balanced \");
return 0;
}
/* Function to push an item to stack*/
void push(struct sNode** top_ref, int new_data)
{
/* allocate node */
struct sNode* new_node =
(struct sNode*) malloc(sizeof(struct sNode));
if (new_node == NULL)
{
printf(\"Stack overflow \ \");
getchar();
exit(0);
}
/* put in the data */
new_node->data = new_data;
/* link the old list off the new node */
new_node->next = (*top_ref);
/* move the head to point to the new node */
(*top_ref) = new_node;
}
/* Function to pop an item from stack*/
int pop(struct sNode** top_ref)
{
char res;
struct sNode *top;
/*If stack is empty then error */
if (*top_ref == NULL)
{
printf(\"Stack overflow \ \");
getchar();
exit(0);
}
else
{
top = *top_ref;
res = top->data;
*top_ref = top->next;
free(top);
return res;
}
}




