BJT Differential Amplifier QuestionSolutionAT DC OPERATING P

BJT Differential Amplifier Question:

AT DC OPERATING POINT :

In active mode ic=ie

ic= 5/20kohms= 0.25 mA=iE

Vc= Vcc-icRc= 15-1.25= 13.75 V

VE= -15V+ iere= -15+ 3.75= -11.25V

VBE=0.7 volts = Vb-VE

VB= VBE+VE= 0.7-11.25V= -10.55V

ib= Vb/rb= 10.55/47 kohms

b) Vocm= (VOP+VON)/2

c) Voutd= (VOP+VON)

d) Ad= Voutd/Vid