The figure below shows the pVdiagram for an isothermal expan

The figure below shows the pV-diagram for an isothermal expansion of 1.00 mol of an ideal gas, at a temperature of 10.5°C.

(a) What is the change in internal energy of the gas?

(b) Calculate the work done by (or on) the gas

Calculate the heat absorbed (or released) by the gas during the expansion.

The internal energy is a state function dependent on temperature. Hence, the internal energy change is zero.

Work done on the gas = nR*T*ln(Vf/Vi)

So, W = 1*8.314*(273+10.5)*ln(0.02/0.01)

= 1633.8 J

So, heat absorbed = 1633.8 J