An airplane comes in for a crash landing at an initial veloc

An airplane comes in for a crash landing at an initial velocity of 255 km/hr and skids on the runaway for 5.00 minutes before coming to rest. How far did the plane travel along the runaway? (in meters) What was the plane\'s deceleration? (m/s/s)

Solution

b.

v = u + at

The plane comes to rest.So the final velocity is zero.

The initial velocity is 255 km/hr which is 70.833 m/s.

The time is 5 mins which is 300 sec

0= 70.833 + (a * 300)

a= 70.833 / (300) = - 0.236 m/s²

a. s= (ut) + (1/2 a t²)

= (70.833 * 300) + (0.5 * -0.236 * 300²)

= 21249.9 + 10620= 10629 m