A cylindrical can is designed to hold 300 ml of liquid The m
A cylindrical can is designed to hold 300 ml of liquid. The material used to construct the sides and the bottom of the can costs 1 cent per cm^2 while the material used for the top costs 2 cents per cm^2. The radius of the can that minimizes the cost is?
Solution
Vol = 300ml = 300cm^3 So, 2pir^2h = 300 r^2h = 47.7 Cost = pir(r+2h) + 2pir^2 Thus r = 12 cm
