Assume that XGFBA andY637 A code consists of 3 different sym

Assume that X={G,F,B,A} andY={6,3,7}. A code consists of 3 different symbols selected from X followed by 3 not necessarily different symbols from Y. How many different codes are possible?

Solution

To get 3 symbols from X, when order matters is 4P3 = 24.

To get 3 symbols from Y, as repetition is allowed, is 3*3*3 = 27.

Thus, a total of 24*27 = 648 codes are possible. [ANSWER]