Given the vectors u 4 6 and v 13 2 find the angle between

Given the vectors u = (4, - 6) and v= (13, - 2), find the angle between the two vectors 47 6 degree 77.2 degree 52 8 degree 4 7 degree

cos theta= u.v/(IuI*IvI)

u=(4,-6) and v=(13,-2)

u.v= 4*13 + (-6)(-2)= 64

IuI= sqrt(4^2 +(-6)^2)= sqrt52 and IvI=sqrt(13^2 +(-2)^2)= sqrt 173

cos theta= 64/(sqrt52 * sqrt 173)= 64/sqrt8996

theta=47.6 degree