Find the number of units x that produces a maximum revenue R

Find the number of units x that produces a maximum revenue R.

R = 171x² 0.06x³

x = units

here R =171x^2-0.06x^3

take derivative wrt x we get

R\'=(171)(2)x-(0.06)(3)x^2

=342x-0.18x^2

take R\'=0 to find maximum revenue

so 342x-0.18x^2=0

x(342-0.18x)=0

x=0,1900

x=0 is not possible

so x=1900 units produces to maximum revenue.

$Find the number of units x that produces a maximum revenue R. R = 171x2 0.06x3 x = unitsSolutionhere R =171x^2-0.06x^3 take derivative wrt x we get R\'=(171)(2)$

Find the number of units x that produces a maximum revenue R

Solution

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