I dont need the work shown I just need the answers in the

At a certain time a particle had a speed of 16 m/s in the positive x direction, and 2.6 s later its speed was 33 m/s in the opposite direction. What is the average acceleration of the particle during this 2.6 s interval? magnitude 19.6 direction [opposite the initial direction of mobon M v Average acceleration is the change in the velocity (from one instant to another) divided by the elapsed time.

Solution

1) a)18.846
   b) opposite to the initial direction of motion

2) figure is inverted;not clear

3) a) 62.62
   b) 57.82
   c) 143.59