Suppose a village needs 15 m3day for water the dynamic head

Suppose a village needs 15 m^3/day for water; the dynamic head is 15 m. Calculate the hydraulic power. Given: Q = 15 m^3/day H = 15 m Formula: P = 10,000 * H * V/t = 10 * Q * H; kW 10*15 m^3/day * 15 m = \"Maybe\"

Solution

Volume of the water needed per day V = 15 m ³ /day

Mass of the water needed per day m = Density of water x V

                                                     = 1000 kg/ m³ x 15 m ³ /day

                                                     =15 x10 ³ kg / day

                                                     = (15 x10 ³ kg) /(24x 60 x60 s)       Since 1 day = 24 hrs = 24 x60 min

                                                                                                                            = 24 x60 x 60 s

                                                     = 0.173611 kg/s

Height of head h = 15 m

Required power P = mgh

                          = (0.173611 kg/s)(9.8m/s ²)(15 m)

                          = 25.52 watt